how to do these questions (103) (97) this is the first part (99) (101) this the second part
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103×97,
(100+3) (100-3),
now using identity
(a+b) (a-b)=a²-b²,
then it becomes
(100²-3²),
10000-9
9991
103×97,
(100+3) (100-3),
now using identity
(a+b) (a-b)=a²-b²,
then it becomes
(100²-3²),
10000-9
9991
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