how to do this help with steps
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Sec theta = x+1/4x Sec²theta = (x+1/4x)²1+tan²theta = x²+1/16x²+1/2 tan²theta = x²+1/16x²+1/2-1tan²theta = x²+1/16x²-1/2tan theta = +-(x-1/4x)when tan theta = +(x-1/4x)then, sec theta+tan theta = x+1/4x+x-1/4x => 2xwhen tha theta = -(x-1/4x)then, sec theta +tan theta = x+1/4x-(x-1/4x) =x+1/4x-x+1/4x=> 1/2x So, sec theta +tan theta = 2x or 1/2x
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pranav605:
can u write in a book or paper and send a pic
Yes I have uploaded now go check it out
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