Question

how to do this one

Answer 1

heya.

1.We have given that,

Initial Velocity=0

Acceleration= 3 m/s²

Time=8 sec

From second equation of motion

 s = ut +(1/2) at²

 By implying values,      

 = 0 + (1/2)×3×(8)²

  = 96 m



2.
Given : 

First Car  A: 

Initial Velocity= u= 52 km/hr=52x5/18=14.4 m/s

Final velocity= V= 0m/s

time =t=5sec

Refer attachment for Graph :

Distance travelled : Area of traingle AOB =1/2 OB x AO

=(1/2)x 14.4 x 5=72/2=36m

Second Car  B:

Initial Velocity= u= 3 km/hr=3x5/18=0.83m/s

Final velocity= V= 0m/s

time =t=10sec

Refer attachment for Graph :

Distance travelled : Area of traingle COD =1/2 OD x CO=(1/2)x 0.83 x 10=4.1m

So, after applying of brakes , Car A has travelled a distance of 3m and car B has travelled a distance of 4.1m.

∴ Car B has travelled farther than Car A after the brakes are applied.

tysm..@gozmit