Question

How to do this one?pls answer briefly

Answer 1

Heya user
Here is your answer !!

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In ∆EDF , EB is the median .

So , its bisects DF .
So ,DB = BF
and BF = 1/2 DF .

Also , DA is the median .
So , AF = 1/2 EF

Now , in the ∆EBF ,
A is the midpoint of EF . ( as AF = 1/2 EF )
AC || EB .
So , C is the midpoint of BF ( converse midpoint theorem ) .

So , CF = 1/2 BF
=> CF = 1/2 ( 1/2 DF )
=> CF = 1/4 DF . [ Proved ] .

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Hope it helps !!