How to do this please help me
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Answers
Answered by
29
Hey there!
Answer:
Refer to the above attachment.
When we divide
+ 6a + 5 by a + 1
In the first step the signs are change and it's become
and
is
.
And in last step the signs are changed again and
is also
.
:
Remainder =![\textbf{0} \textbf{0}](https://tex.z-dn.net/?f=%5Ctextbf%7B0%7D)
=
.
:
=( a + 1 ) ( a + 5 )
=
+ 5a + a + 5
=
+ 6a + 5
Hope this will help you.
Love Brainly.
#Be Brainly.
Answer:
Refer to the above attachment.
When we divide
In the first step the signs are change and it's become
And in last step the signs are changed again and
Remainder =
=( a + 1 ) ( a + 5 )
=
=
Hope this will help you.
Love Brainly.
#Be Brainly.
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Answered by
7
Hello mate.
Thanks for asking this useful question.
![Your\: answer\:is=> Your\: answer\:is=>](https://tex.z-dn.net/?f=Your%5C%3A+answer%5C%3Ais%3D%26gt%3B)
let , our final value of division be 'x'
so we can write our equation as ,
![\boxed {\frac {a^{2}+6a+5}{a+1}\:\:=\:x} \boxed {\frac {a^{2}+6a+5}{a+1}\:\:=\:x}](https://tex.z-dn.net/?f=+%5Cboxed+%7B%5Cfrac+%7Ba%5E%7B2%7D%2B6a%2B5%7D%7Ba%2B1%7D%5C%3A%5C%3A%3D%5C%3Ax%7D)
![=>\:a^{2}+6a+5\:=\:(a+1)x =>\:a^{2}+6a+5\:=\:(a+1)x](https://tex.z-dn.net/?f=%3D%26gt%3B%5C%3Aa%5E%7B2%7D%2B6a%2B5%5C%3A%3D%5C%3A%28a%2B1%29x)
®by using factorisation method® ,
![=>\:a^{2}+5a+a+5\:=\:(a+1)x =>\:a^{2}+5a+a+5\:=\:(a+1)x](https://tex.z-dn.net/?f=%3D%26gt%3B%5C%3Aa%5E%7B2%7D%2B5a%2Ba%2B5%5C%3A%3D%5C%3A%28a%2B1%29x)
![=>\:a(a+5)+1(a+5)\:=(a+1)x =>\:a(a+5)+1(a+5)\:=(a+1)x](https://tex.z-dn.net/?f=%3D%26gt%3B%5C%3Aa%28a%2B5%29%2B1%28a%2B5%29%5C%3A%3D%28a%2B1%29x)
![=>\:(a+1)(a+5)\:=\:(a+1)x =>\:(a+1)(a+5)\:=\:(a+1)x](https://tex.z-dn.net/?f=%3D%26gt%3B%5C%3A%28a%2B1%29%28a%2B5%29%5C%3A%3D%5C%3A%28a%2B1%29x)
dividing both sides by (a+1) ,
![=> \cancel {(a+1)}(a+5)\: =\: \cancel{(a+1)}x => \cancel {(a+1)}(a+5)\: =\: \cancel{(a+1)}x](https://tex.z-dn.net/?f=%3D%26gt%3B+%5Ccancel+%7B%28a%2B1%29%7D%28a%2B5%29%5C%3A+%3D%5C%3A+%5Ccancel%7B%28a%2B1%29%7Dx)
![=>(a+5)\:=\:x =>(a+5)\:=\:x](https://tex.z-dn.net/?f=%3D%26gt%3B%28a%2B5%29%5C%3A%3D%5C%3Ax)
hence ,
![\boxed {\frac{a^{2}+6a+5}{a+1}\:=\:a+5} \boxed {\frac{a^{2}+6a+5}{a+1}\:=\:a+5}](https://tex.z-dn.net/?f=+%5Cboxed+%7B%5Cfrac%7Ba%5E%7B2%7D%2B6a%2B5%7D%7Ba%2B1%7D%5C%3A%3D%5C%3Aa%2B5%7D)
hope u understood ^_^
BeBRAINLY
BeHAPPY
Thanks for asking this useful question.
let , our final value of division be 'x'
so we can write our equation as ,
®by using factorisation method® ,
dividing both sides by (a+1) ,
hence ,
hope u understood ^_^
BeBRAINLY
BeHAPPY
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