Question

How to do this please help me

Answer 1

Hey there!


Answer:
Refer to the above attachment.


When we divide $a^{2}$ + 6a + 5 by a + 1


In the first step the signs are change and it's become $\textbf{( + ) to ( - )}$ and $a^{2}$ is $\textbf{cancelled out}$.


And in last step the signs are changed again and $\textbf{5a is cancelled and 5 }$is also $\textbf{cancelled}$.


$\textbf{So We Get}$:


Remainder = $\textbf{0}$


$\textbf{Quotient}$ = $\textbf{a + 5}$.


$\textbf{To check this}$ :

=( a + 1 ) ( a + 5 )


= $a^{2}$ + 5a + a + 5


= $a^{2}$ + 6a + 5


Hope this will help you.


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Answer 2

Hello mate.

Thanks for asking this useful question.

$Your\: answer\:is=>$

let , our final value of division be 'x'

so we can write our equation as ,

$\boxed {\frac {a^{2}+6a+5}{a+1}\:\:=\:x}$


$=>\:a^{2}+6a+5\:=\:(a+1)x$


®by using factorisation method® ,


$=>\:a^{2}+5a+a+5\:=\:(a+1)x$


$=>\:a(a+5)+1(a+5)\:=(a+1)x$


$=>\:(a+1)(a+5)\:=\:(a+1)x$


dividing both sides by (a+1) ,


$=> \cancel {(a+1)}(a+5)\: =\: \cancel{(a+1)}x$


$=>(a+5)\:=\:x$

hence ,


$\boxed {\frac{a^{2}+6a+5}{a+1}\:=\:a+5}$


hope u understood ^_^



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