How to do this? Please help me out!
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Amanjagwan:
11th ka hai kya ye
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(i^25)^3
= (i)^75
you know
i^1 = i
i^2 = -1
i^3 = -i
then i^75 = i3 = i2 * i = -i
Polar form:
r = |z| = 1
φ = arg z = -90° = -0.5π = -π/2
= (i)^75
you know
i^1 = i
i^2 = -1
i^3 = -i
then i^75 = i3 = i2 * i = -i
Polar form:
r = |z| = 1
φ = arg z = -90° = -0.5π = -π/2
Thank you! :)
welcome miss
Answered by
1
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Thank you!
welcome miss
ohh m sorry
Sorry? For what?
miss actually i comment on a other girl answer
Oh, yeah I just saw it right now. It's fine. Chill.
welcome........ I don't want any other guys disturb so i say sorry.........
Oh. It's absolutely fine. :)
thanks a lot
My pleasure!
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