how to do this ? plse help me
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y=77° and X=50° because AB parallel to CD
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Extend PR Upwards until a point and name it some X, Now by properties of Parallel lines,
Angle XPB = 127°,
Now Angle XPA = 180°-127° = 53°,
Now We also know that RX is a line, and angle on RX must be 180°,
=> 53°+50°+y = 180° ,
=> y = 77°,
By properties of triangle, We also know that, Angle PRD = y +x,
=> 127° = 77° + x,
=> x = 50°,
So therefore x = 50°, and y = 77°,
Hope yo understand, Have a great day !
Angle XPB = 127°,
Now Angle XPA = 180°-127° = 53°,
Now We also know that RX is a line, and angle on RX must be 180°,
=> 53°+50°+y = 180° ,
=> y = 77°,
By properties of triangle, We also know that, Angle PRD = y +x,
=> 127° = 77° + x,
=> x = 50°,
So therefore x = 50°, and y = 77°,
Hope yo understand, Have a great day !
Thestudyworm:
thnx a lot
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