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the distance covered by x
X/10+y/10=--2
X/10-y/10=3
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Let the speed of the train be 'x'km/h and the time taken by train to travel the given distance be 't' hours and the distance to travel be 'd'km.
We know that,
⇒Speed=
⇒x=
∴d=xt.......(i)
Case 1
⇒(x+10)×(t−2)=d
⇒xt+10t−2x−20=d
⇒d+10t−2x−20=d
⇒−2x+10t=20...... (ii)
Case 2
⇒(x−10)×(t+3)=d
⇒xt−10t+3x−30=d
⇒d−10t+3x−30=d
⇒3x−10t=30......... (iii)
Adding equations (ii) and (iii), we get
⇒x=50
Substitute the value of x in (ii) we get
⇒(−2)×(50)+10t=20
⇒−100+10t=20
⇒10t=120
⇒t=12 hours
Substitute the value of t and x in equation (i), we get
Distance to travel =d=xt
⇒d=12×50=600Km
Hence, the distance covered by the train is 600km.
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