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distance given is 90km and let the initial time taken be t hr
so time velocity initially will be
from velocity* time= distance
so velocity= 90/t
case 2
given time taken is t-(1/2hour)
velocity is 15kmph more so velocity =90/t +15
distance is 90
so 90= (t-0.5)*(90/t +15)
solving this we get t as 2hrs. so it initially took 2hrs
so time velocity initially will be
from velocity* time= distance
so velocity= 90/t
case 2
given time taken is t-(1/2hour)
velocity is 15kmph more so velocity =90/t +15
distance is 90
so 90= (t-0.5)*(90/t +15)
solving this we get t as 2hrs. so it initially took 2hrs
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Answer:
Step-by-step explanation:15-28x=36
15-36=28x
21=28x
21÷28=x
3/4=x
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