how to do this question guys
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hi Diana,
b)
In triangle PQR,
<QRP = 90
so by pythagoras theorem,
PR^2 + QR^2 = PQ^2
QR^2 = PQ^2 - PR^2
= (2*OQ)^2 - 12^2
= 13^2 - 144
= 169 - 144
= 25
QR = 5cm
b)
In triangle PQR,
<QRP = 90
so by pythagoras theorem,
PR^2 + QR^2 = PQ^2
QR^2 = PQ^2 - PR^2
= (2*OQ)^2 - 12^2
= 13^2 - 144
= 169 - 144
= 25
QR = 5cm
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