Question

How to do this Question number 3

Answer 1

Answer:

ABCD is a rhombus

Step-by-step explanation:

Quadrilateral ABCD in which AC and BD intersect each other at right angles at O.

In ΔOAB and ΔOCB,

⇒ OA = OC

⇒ OB = OB

⇒ ∠AOB = ∠COB {Each = 90°}

⇒ ΔOAB ≅ ΔOCB

⇒ AB = BC.

Therefore, ABCD is a rhombus.

Hope it helps!