Question

How to do this question. Pls help me. ​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Let AP = 60 m be the height of the window.

CD = h m be the height of the house.

GIVEN:

∠QPD = 60°

∠QPC = 45°  (angle of depression of the foot C of the house CD)

QD = CD - CQ

QD = CD - AP        [CQ = AP]

QD =  (h - 60) m

In ∆PQC,

=> tan 45° = QC/PQ = P/B

=> 1 = 60/PQ

=> PQ = 60 m

In ∆PQD ,

tan 60° = QD/PQ = P/B

√3 = (h-60)/60

60√3 = (h-60)

60√3 +60 = h

60(√3+1) = h

Hence, the height of the opposite house is 60(√3+1) m.

Hope it helps!