Math, asked by yadavvaibhav, 9 months ago

how to do this step by step ​

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Answered by uneq95
0

Step-by-step explanation:

Solution for (i) 1728

Just list down the factors of 1728

1728 =  {2}^{6}  \times  {3}^{3}

If you take the root of it,

 \sqrt{1728}  =  {2}^{3}  \times 3 \times  \sqrt{3}

This factor of 3 is limiting 1728 from becoming a perfect square.

Hence we need to divide 1728 by 3 to obtain a perfect square.

The perfect square number would be 2³×3 = 24

Similarly, you can proceed for other options too.

Small tip: You need to understand that a number would be perfect square if and only if all the prime factors which compose the number have even powers. In the case of 1728, we have two factors, 2 and 3. 2 has the power 6 and 3 has the power 3. Since, 2 has even power we are going to ignore it and focus on 3 which has odd power (3).

What is the minimum we can do to reduce the power of prime factor 3 to an even number. The closest even power is 2. Hence, we divide the whole number by 3¹.

Answered by Anonymous
0

Answer:

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