Question

how to do this step please tell..........

Answer 1

Given numbers : 2 , 3 , 4 , 5 , 0 , 1 , 3 , 3 , 4 , 3.

$\boxed{\mathsf{Mean = \dfrac{Sum\:of\:quantities}{Number\:of\:quantities}}}$

Therefore,

$\text{mean of the given numbers } = \dfrac{2+3+4+5+0+1+3+3+4+3}{10}\\\\\\\quad\quad = \dfrac{28}{10}\\\\\quad\quad = 2.8$

Therefore mean of the given numbers is 2.8

( ii ) : Median.

First we have to arrange the given numbers in ascending  / descending order.

So, numbers are 0 , 1 , 2 , 3 , 3 , 3 , 3 , 4 , 4 , 5

When, number of quantities is even,

$\mathsf{Median =\dfrac{\dfrac{n}{2}th\:term + \bigg( \dfrac{n}{2} + 1 \bigg)th \:term }{2}}$

Therefore,

$\mathsf{Median\;of\;the\;given\;numbers = \dfrac{\dfrac{5}{2}th\:term + \bigg( \dfrac{10}{2} + 1 \bigg)th \:term }{2}}$

Median of the given numbers = { 5th term + 6th term ) / 2

Median of the given numbers = { 3 + 3 } / 2

Median of the given numbers = 6 / 2

Median of the given number = 3