Question

how to do this sum?

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Answer 1

firstly , it is a multiply .

$( \frac{5c {}^{4} b {}^{3} }{a { }^{2} }) {}^{3} \times (\frac{a {}^{2} }{4b {}^{2} c {}^{5} } ) {}^{2} \\ \frac{125c {}^{12}b {}^{9} }{a {}^{6} } \times \frac{a {}^{4} }{16b {}^{4} c {}^{10} } \\= \frac{125b {}^{5}c {}^{2} }{16a {}^{2} }$