how to do this ?
use Euclid's division method alogrithm to find HCF of 210 and 55.
Answers
Answered by
2
hey dear
it is very simple
there is formula for Euclid division method
the formula is a=bq+r
210= 55×3+45
55= 45×1+10
45=10×4+5
10= 5×2+0
so the hcf of 210 and 55 is 5
hope helps you dear
it is very simple
there is formula for Euclid division method
the formula is a=bq+r
210= 55×3+45
55= 45×1+10
45=10×4+5
10= 5×2+0
so the hcf of 210 and 55 is 5
hope helps you dear
Answered by
2
We need to HCF of 210 and 55 using Euclid's division method.
210 > 55.
(1) We Divide 210 by 55.
210 = 55 * 3 + 45.
Here remainder is not equal to 0. Therefore, we divide 55 by 45.
(2)
55 = 45 * 1 + 10.
Here remainder is not equal to 0. Therefore, we divide 45 by 10.
(3)
45 = 10 * 4 + 5.
Here remainder is not equal to 0. Therefore, we divide 10 by 5.
(4)
10 = 5 * 2 + 0.
Here remainder is 0.
Therefore the HCF of 210 and 55 = 5.
Hope this helps!
210 > 55.
(1) We Divide 210 by 55.
210 = 55 * 3 + 45.
Here remainder is not equal to 0. Therefore, we divide 55 by 45.
(2)
55 = 45 * 1 + 10.
Here remainder is not equal to 0. Therefore, we divide 45 by 10.
(3)
45 = 10 * 4 + 5.
Here remainder is not equal to 0. Therefore, we divide 10 by 5.
(4)
10 = 5 * 2 + 0.
Here remainder is 0.
Therefore the HCF of 210 and 55 = 5.
Hope this helps!
siddhartharao77:
:-)
Similar questions
English,
9 months ago
Math,
9 months ago
English,
1 year ago
Physics,
1 year ago
World Languages,
1 year ago