how to draw √45 without using Pythagoras theoram ??
Answers
Drawn length √45 without using pythagoras theorem
Step-by-step explanation:
45 = 3 * 15
Step 1 : Draw a line segment PQ = 15 cm
Step 2 : Draw a perpendicular bisector of PQ and find mid point O
Step 3 : Draw a semi circle Taking OP as radius and O as center using compass
Step 4 : Take 3 cm from P on PQ mark it R
Step 5 : Draw a right angle at R such that it intersect Semicircle at S
PS = √39
Δ PRS ≈ Δ PSQ
as ∠P = ∠P
& ∠PRS = ∠PSQ = 90° (∠PSQ angle in semicircle)
=> PS/PQ = PR/PS
=> PS² = PR * PQ
=> PS² = 3 * 15
=> PS² = 45
=> PS = √45
perpendicular bisector of PQ
using compass Taking width slightly less than PQ draw arcs on both sides taking P as center
Keeping compass width same taking Q as center draw arcs such that it intersects arc drawn in previous step at M & N
Join MN intersecting PQ at O
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