Question

how to draw a parallelogram abcd in which bc=5.6cm and diagonal ac=6.8cm

Answer 1

Let AC and BD are the diagonal of the parallelogram which intersects each other at point O.

Now, AO = OC = AC/2 = 6.2/2 = 3.1

And BO = OD = BD/2 = 8/2 = 4

Construction:

1. Draw a line segment BC of length 5.6 cm

2. Now, take B as center and draw an arc length of 4 cm

3. Again, take C as center and draw an arc length of 3.1 cm which intersect the previous arc at point O

4. Now, join O to B and C

5. Extend BO to D such that BD = 8

6. Extend CO to A such that AC = 6.2

7. Finally, join A to B, A to D and C to D.

This is the required parallelogram ABCD