Question

how to evaluate
answer! please
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Answer 1

Answer:

Step-by-step explanation:

X=9

Answer 2

Given :

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• $\tt \: \dfrac{x - 3}{2x - (x - 3)} = \dfrac{x - 2}{(2x + 3) - (x - 2)}$

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To Find :

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• Value of x.

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Solution :

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$\tt:\implies \: \dfrac{x - 3}{2x - (x - 3)} = \dfrac{x - 2}{(2x + 3) - (x - 2)} \\ \\ \\ \tt:\implies \: \frac{x - 3}{2x - x + 3} = \frac{x - 2}{2x + 3 - x + 2} \\ \\ \\ \tt:\implies \: \frac{x - 3}{x + 3} = \frac{x - 2}{2x - x + 3 + 2} \\ \\ \\ \tt:\implies \: \frac{x - 3}{x + 3} = \frac{x - 2}{x + 5} \\ \\ \\ \tt:\implies \: (x - 3)(x + 5) = (x + 3)(x - 2) \\ \\ \\ \tt:\implies \: \cancel {x}^{2} - 3x + 5x - 15 = \cancel x {}^{2} + 3x - 2x - 6 \\ \\ \\ \tt:\implies \: 5x - 3x - 15 = 3x - 2x - 6 \\ \\ \\ \tt:\implies \: 2x - 15 = x - 6 \\ \\ \\ \tt:\implies \: 2x - x = 15 - 6 \\ \\ \\ \tt:\implies \: x = \underline{\boxed{\tt\purple{9}}}\bigstar \\ \\ \\ \\ \tt\therefore{\underline{Hence, \: the \: value \: of \: x \: is \: \bold{9}}}.$