How to express 13 square as the sum of 2 consecutive natural integers
Answers
Answered by
174
Let the numbers be x,x+1
13² = 169
x+x+1 = 169
2x = 169-1
2x = 168
x = 168/2
x = 84
so the numbers are 84 and 85
Hope it helps u : )
13² = 169
x+x+1 = 169
2x = 169-1
2x = 168
x = 168/2
x = 84
so the numbers are 84 and 85
Hope it helps u : )
Answered by
81
Hello Dear!!!
Here's your answer...
Let,
The two consecutive integers are
y,y+1
The sum of these two numbers is (13)^2
(13)^2 = y+y+1
169 = 2y+1
169-1 = 2y
168 = 2y
168/2 = y
84 = y
y is 84
y+1 is 85.
The numbers are 84 and 85...
_____________________________
Hope this helps you....
Here's your answer...
Let,
The two consecutive integers are
y,y+1
The sum of these two numbers is (13)^2
(13)^2 = y+y+1
169 = 2y+1
169-1 = 2y
168 = 2y
168/2 = y
84 = y
y is 84
y+1 is 85.
The numbers are 84 and 85...
_____________________________
Hope this helps you....
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