How to express 29 as a difference of squares
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(28-1)(28+1) = (28) whole square -( 1 )square = 784-1 = 783
we know that( a+b)(a-b) = (a)square -(b) square
THANKS
@trisha_:)
we know that( a+b)(a-b) = (a)square -(b) square
THANKS
@trisha_:)
vishwas60:
hlo g
Answered by
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Answer :
We know : 29 is a prime number , So
29 = 29 × 1
And
Difference of two square = 29 , So
x^2 - y^2 = 29
( x + y ) ( x - y ) = 29 (
We know x^2 - y^2 = ( x + y ) ( x - y ) )
And
29 = 29 × 1
So,
x + y = 29
And
x - y = 1 , We add both equation and get
2x = 30
x = 15 , Substitute that we get
15 + y = 29
y = 14
So,
15^2 - 14^2 = 29
#Be Brainly✌️
We know : 29 is a prime number , So
29 = 29 × 1
And
Difference of two square = 29 , So
x^2 - y^2 = 29
( x + y ) ( x - y ) = 29 (
We know x^2 - y^2 = ( x + y ) ( x - y ) )
And
29 = 29 × 1
So,
x + y = 29
And
x - y = 1 , We add both equation and get
2x = 30
x = 15 , Substitute that we get
15 + y = 29
y = 14
So,
15^2 - 14^2 = 29
#Be Brainly✌️
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