Question

how to factorise 108a² - 3(b-c)²​

Answer 1

Answer:

108a² - 3(b - c)² = 3(6a + b - c)(6a - b + c)

Step-by-step explanation:

108a² - 3(b - c)²

= 3 [36a² - (b - c)²]

= 3 [(6a)² - (b - c)²]

Using identity x² - y² = (x + y)(x - y). Here x = 6a and y = b - c

= 3(6a + b - c)[6a - (b - c)]

= 3(6a + b - c)(6a - b + c)

Hope this helps! :)

Answer 2

answer is 3a(6a+b-c)(6a-b+c)