how to factorise 11 y square - 98 Y - 120 is equal to zero
Answers
Answer:
(11y+12) × (y-10)=0
Step-by-step explanation:
Trying to factor by splitting the middle term
2.1 Factoring 11y2-98y-120
The first term is, 11y2 its coefficient is 11 .
The middle term is, -98y its coefficient is -98 .
The last term, "the constant", is -120
Step-1 : Multiply the coefficient of the first term by the constant 11 • -120 = -1320
Step-2 : Find two factors of -1320 whose sum equals the coefficient of the middle term, which is -98 .
-1320 + 1 = -1319
-660 + 2 = -658
-440 + 3 = -437
-330 + 4 = -326
-264 + 5 = -259
-220 + 6 = -214
-165 + 8 = -157
-132 + 10 = -122
-120 + 11 = -109
-110 + 12 = -98 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -110 and 12
11y2 - 110y + 12y - 120
Step-4 : Add up the first 2 terms, pulling out like factors :
11y • (y-10)
Add up the last 2 terms, pulling out common factors :
12 • (y-10)
Step-5 : Add up the four terms of step 4 :
(11y+12) • (y-10)
Which is the desired factorization
hence the answer is
(11y+12) × (y-10)=0
Answer:
11y2-98y-120 can be factorise by using splitting equation method
Step-by-step explanation:
1)multiply 11 n 120=1320
2)make factores od 1320
3)we get 2*2*2*3*5*11
4)5*2*11=110 n 2*2*3=12
5)110-12=98
so we can write guven equation as 11y2-110y+12y-120
by taking common
11y(y-10)+12(y-10)
(11y+12)(y-10)
so y=10 and y=-12/11
HOPE IT HELP U