how to factorise 24x^2+9x+5
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Equation at the end of step 1 :
((23•3x2) + 9x) + 5
Step 2 :
Trying to factor by splitting the middle term
2.1 Factoring 24x2+9x+5
The first term is, 24x2 its coefficient is 24 .
The middle term is, +9x its coefficient is 9 .
The last term, "the constant", is +5
Step-1 : Multiply the coefficient of the first term by the constant 24 • 5 = 120
Step-2 : Find two factors of 120 whose sum equals the coefficient of the middle term, which is 9 .
-120 + -1 = -121 -60 + -2 = -62 -40 + -3 = -43 -30 + -4 = -34 -24 + -5 = -29 -20 + -6 = -26
For tidiness, printing of 26 lines which failed to find two such factors, was suppressed
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Final result :
24x2 + 9x + 5
((23•3x2) + 9x) + 5
Step 2 :
Trying to factor by splitting the middle term
2.1 Factoring 24x2+9x+5
The first term is, 24x2 its coefficient is 24 .
The middle term is, +9x its coefficient is 9 .
The last term, "the constant", is +5
Step-1 : Multiply the coefficient of the first term by the constant 24 • 5 = 120
Step-2 : Find two factors of 120 whose sum equals the coefficient of the middle term, which is 9 .
-120 + -1 = -121 -60 + -2 = -62 -40 + -3 = -43 -30 + -4 = -34 -24 + -5 = -29 -20 + -6 = -26
For tidiness, printing of 26 lines which failed to find two such factors, was suppressed
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Final result :
24x2 + 9x + 5
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