Question

How to Factorise 2y²-8y+6

Answer 1

Step-by-step explanation:

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Answer 2

$2 {y}^{2} - 8y + 6 \\ = 2( {y}^{2} - 4y + 3) \\ = 2( {y}^{2} - 3y - y + 3) \\ =2( y(y - 3) - 1(y - 3))$

$= 2(y - 1)(y - 3)$