How to factorise 3a³-9a²+6a
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Answered by
7
Hey dear!
Here is yr answer.....
=> 3a³ - 9a² + 6a
=> 3a(a²-3a+2)
=> 3a(a²-2a-a+2)
=> 3a [a(a-2) + 1(a-2) ]
=> 3a [ (a-2) (a-1) ]
Hope it hlpz..
Here is yr answer.....
=> 3a³ - 9a² + 6a
=> 3a(a²-3a+2)
=> 3a(a²-2a-a+2)
=> 3a [a(a-2) + 1(a-2) ]
=> 3a [ (a-2) (a-1) ]
Hope it hlpz..
Answered by
1
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hope it helps you dear...
see in the attached picture...
if it helps you dear friend so plz mark as brainliest....
thankyou!
follow me guys....
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