Question

How to factorise (3x + 1)(2x + 5)

Answer 1

Answer:

$(3x + 1)(2x + 5) = 0\\ (6x {}^{2} + 15x + 2x + 5) = 0 \\ 6x {}^{2} + 17x + 5 = 0 \\ 6x {}^{2} + 15x + 2x+ 5 = 0 \\ 3x(2x + 5) + 1(2x + 5) = 0 \\ (2x + 5)(3x + 1) = 0 \\ x = \frac{ - 5}{2} \: \: and \: \: \frac{ - 1}{3}$

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