How to factorise 4n^2+5n-636, by doing prime factorisaton of 636?
Answers
Answered by
20
Hey friend
Here is your answer
=4n²+5n-636
=4n²+(53-48)n-636
=4n²+53n-48n-636
=n(4n+53)-12(4n+53)
=(4n+53)(n-12)
HOPE THIS HELPS YOU
Here is your answer
=4n²+5n-636
=4n²+(53-48)n-636
=4n²+53n-48n-636
=n(4n+53)-12(4n+53)
=(4n+53)(n-12)
HOPE THIS HELPS YOU
Prashant24IITBHU:
Good one
Answered by
13
Given Equation is 4n^2 + 5n - 636
= > 4n^2 - 48n + 53n - 636
= > 4n(n - 12) + 53(n - 12)
= > (4n + 53)(n - 12).
Prime factorization of 636 = 2^2 * 3 * 53.
Hope this helps!
= > 4n^2 - 48n + 53n - 636
= > 4n(n - 12) + 53(n - 12)
= > (4n + 53)(n - 12).
Prime factorization of 636 = 2^2 * 3 * 53.
Hope this helps!
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