How to factorise :-
4x^4+81y^4
Answers
Answer:
( 2x² + 9y² + 6xy ) ( 2x² + 9y² - 6xy )
Step-by-step explanation:
To find -----> Factors of 4x⁴ + 81 y⁴
Solution------> We know that ,
4 x⁴ = ( 2 )² ( x² )²
= ( 2x² )²
81 y⁴ = ( 9 )² ( y² )²
= ( 9y² )²
Now ,
4x⁴ + 81y⁴ = ( 2x² )² + ( 9y² )²
Now , let , a = 2x² and b = 9y² , putting in above
= ( a )² + ( b )²
Now adding and subtracting 2ab , to make it perfect square ,
= ( a )² + ( b )² + 2 ab - 2ab
= ( a² + b² + 2ab ) - 2ab
We know that , ( x + y )² = x² + y² + 2xy , applying it , we get,
= ( a + b )² - 2 ab
= ( 2x² + 9y² )² - 2 ( 2x² ) ( 9y² )
= ( 2x² + 9y² )² - 36 x² y²
= ( 2x² + 9y² )² - ( 6xy )²
We know that , a² - b² = ( a + b ) ( a - b ) , applying it , we get,
= ( 2x² + 9y² + 6xy ) ( 2x² + 9y² - 6xy )
Answer:
fegwtwwtwt2t3t
bsbshsgdgd
bsbsheywgsvcx
dhdhrhdydgdgdvex
sagsgxgdgxgdvgd
why 62teg4rggdvdvrvd x.dx.dnndjsjqoq910jxjdjheheryrr