Math, asked by arcadeaadhi, 5 months ago

How to factorise 4xy^(3y-x)-2x^(x-3y)^

Answers

Answered by januu36
0

Step-by-step explanation:

STEP

1

:

Equation at the end of step 1

((4x•(y2))•(3y-x))-(2x2•(x-3y)2)

STEP

2

:

Equation at the end of step 2

((4x•(y2))•(3y-x))-2x2•(x-3y)2

STEP

3

:

Equation at the end of step

3

:

(22xy2 • (3y - x)) - 2x2 • (x - 3y)2

STEP

4

:

Equation at the end of step 4

22xy2 • (3y - x) - 2x2 • (x - 3y)2

STEP

5

:

Pulling out like terms

5.1 Pull out 3y-x

Note that x-3y =(-1)• 3y-x

After pulling out, we are left with :

(3y-x) • ( 22xy2 * (-1) +( 2x2 * (x-3y) ))

STEP

6

:

Pulling out like terms

6.1 Pull out like factors :

2x3 - 6x2y - 4xy2 = 2x • (x2 - 3xy - 2y2)

Trying to factor a multi variable polynomial :

6.2 Factoring x2 - 3xy - 2y2

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