Question

How to factorise 8/27 x^3 - 1/8 y^3

Answer 1

Step-by-step explanation:

$use \: property \: a \: cube - \: bcube$

${( \frac{2x}{3} )}^{3} - {( \frac{1y}{2} )}^{3} \\( \frac{2x}{3} - \frac{y}{2} )( \frac{4 {x}^{2} }{9} + {y}^{2} + \frac{2xy}{3} ) \\ \\ this \: is \: your \: answer$