how to factorise 8x^3-(2x-y)^3.…??? pls answer fast!!
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8x^3-(2x-y)^3
= (2x)^3-(2x-y)^3
Apply formula a3 - b3 = (a - b)3 + 3 a b (a - b)
= put a=2x,b= 2x-y
= (2x-2x+y)^3+3(2x)(2x-y)(2x-2x+y)
= y^3+6xy(2x-y)
=y^3+12x^2y-6xy^2
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