Question

how to factorise 9(2a-b)^2-4(2a-b)-13?

Answer 1

Answer:

here you go sorry i havent seen your qns ..well i answerd thanks

Answer 2

Answer:

(2a-b+1)(18a-9b-13)

Step-by-step explanation:

Lets take 2a-b=x

Substituting x in the equation given:

9(2a-b)^2-4(2a-b)-13=0

9x^2-4x-13=0

9x^2-13x+9x-13=0

[In this step we have to carefully see the sum of the factors and the product of the factors since the product =(-13) x 9x^2 and sum =-4x=-13x +9x, We take that ]

x(9x-13)+1(9x-13)=0

(x+1)(9x-13)=0

Now taking 2a-b =x back

we get

(x+1)[9(2a-b)-13]=0

(2a-b+1)(18a-9b-13)=0

Hence this is your ans.

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