Math, asked by binadihettiarachchi6, 6 hours ago

How to factorise this?​

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Answers

Answered by TheDEVIL001
1

Answer:

 {4a}^{2}  -  {7}^{2}

 | 4a - 7| \times  | 4a + 7 |

Answered by Itzkamina5
2

Use the sum-product pattern

16²- 49

\16a²{2}{\color{#c92786}{-49}}

16a2−4912+28−28−49

\16a^{2}+{\color{#c92786}{28a}}

\{\color{#c92786}{-28a}}-49

16a²+28a−28a−49²

Common factor from the two pairs

16²+28−28−49

16a²{2}+28a-28a-49

16a²+28a−28a−49

4(4+7)−7(4+7)

4a(4a+7)-7(4a+7)

4a(4a+7)−7(4a+7)3

Rewrite in factored form

4(4+7)−7(4+7)

4a(4a+7)-7(4a+7)

4a(4a+7)−7(4a+7)

(4−7)(4+7)

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