how to factorise this two numbers
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18) a²+b²-c²-d²+2ab-2cd
= (a²+b²+2ab)-(c²+d²+2cd)
∴ identity used => (a+b)² = a²+b²+2ab
= (a+b)² - (c+d)²
= (a+b)(a+b) - (c+d)(c+d)
19) 4x² -12ax-y²-z²-2yz+9a²
= 4x²+9a²-12ax -y²-z²-2yz
= { (2x)²+(3a)²-2*2x*3a } - { (y)²+(z)²+2*y*z }
∴ identity => a²+b²-2ab = (a-b)² , a²+b²+2ab = (a+b)²
= (2x-3a)² - (y+z)²
= (2x-3a)(2x-3a) - (y+z)(y+z)
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= (a²+b²+2ab)-(c²+d²+2cd)
∴ identity used => (a+b)² = a²+b²+2ab
= (a+b)² - (c+d)²
= (a+b)(a+b) - (c+d)(c+d)
19) 4x² -12ax-y²-z²-2yz+9a²
= 4x²+9a²-12ax -y²-z²-2yz
= { (2x)²+(3a)²-2*2x*3a } - { (y)²+(z)²+2*y*z }
∴ identity => a²+b²-2ab = (a-b)² , a²+b²+2ab = (a+b)²
= (2x-3a)² - (y+z)²
= (2x-3a)(2x-3a) - (y+z)(y+z)
I HOPE THIS ANSWER WAS HELPFUL TO YOU...............................
THANK YOU
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