Math, asked by shivam874, 1 year ago

how to factorise with suitable identities 4y²-4y+1

Answers

Answered by yashraj7921

41

4y²–4y+1
(4y²-2y)-(2y+1)
2y(2y-1)+(2y-1)
(2y-1) (2y-1)

Answered by shaikjaveedpasha2018

7

Step-by-step explanation:

4y²_4y+1

(4y²_2y)_(2y+1)

2y (2y_1)+(2y_1)

(2y_1)(2y_1)

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