how to factorise x^4+8x
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shuklamohit1296:
bhaiya pura factorise karo
options x^2+2 , x^2+8, x+2 , x-2 hai
but how bro?
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![{x}^{4} + 8x = 0 \\ (x)( {x}^{3} + 8 ) \\ \\ hence \: x = 0 \: and \: \sqrt[3]{ - 8}](https://tex.z-dn.net/?f=+%7Bx%7D%5E%7B4%7D+%2B+8x+%3D+0+%5C%5C+%28x%29%28+%7Bx%7D%5E%7B3%7D+%2B+8+%29+%5C%5C+%5C%5C+hence+%5C%3A+x+%3D+0+%5C%3A+and+%5C%3A+%5Csqrt%5B3%5D%7B+-+8%7D+ "{x}^{4} + 8x = 0 \\ (x)( {x}^{3} + 8 ) \\ \\ hence \: x = 0 \: and \: \sqrt[3]{ - 8}")
or -2
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or -2
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its wrong
answer is not present in my textbook otions
plzz write option
x^2+2, x^2+8, x+2, x-2
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