how to factorise x3-5x2-x+5 by x-1
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Solution is in the following pic is this helpful for you
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x-1=0
x=1
p(x)=x^3-5x^2-x+5 =0
p(1)=(1)^3-5(1)^2-(1)+5 =0
1-5-1+5 =0
-4+4 =0
=0 =0
pls mark as brainliest if you like
x=1
p(x)=x^3-5x^2-x+5 =0
p(1)=(1)^3-5(1)^2-(1)+5 =0
1-5-1+5 =0
-4+4 =0
=0 =0
pls mark as brainliest if you like
tonystark82:
tell me in factor form
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