how to factorise x3-5x2-x+5 by x-1
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Solution is in the following pic is this helpful for you
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x-1=0
x=1
p(x)=x^3-5x^2-x+5 =0
p(1)=(1)^3-5(1)^2-(1)+5 =0
1-5-1+5 =0
-4+4 =0
=0 =0
pls mark as brainliest if you like
x=1
p(x)=x^3-5x^2-x+5 =0
p(1)=(1)^3-5(1)^2-(1)+5 =0
1-5-1+5 =0
-4+4 =0
=0 =0
pls mark as brainliest if you like
tonystark82:
tell me in factor form
What are you saying pls tell in detail
this is factor form only
this is in remainder form
factor theorem se batao
Pls check the ans now
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