Math, asked by hanisha1738, 17 hours ago

How to factorize 49x^{2} - 16y^{2}].​

Pls help

Answers

Answered by galacticnike541
1

Answer:

Rewrite 49x2 49 x 2 as (7x)2 ( 7 x ) 2 . Rewrite 16y2 16 y 2 as (4y)2 ( 4 y ) 2 . Since both terms are perfect squares, factor using the difference of squares formula, a2−b2=(a+b)(a−b) a 2 - b 2 = ( a + b ) ( a - b ) where a=7x a = 7 x and b

Answered by shrutibaghel42
2

Step-by-step explanation:

Multiply the number

49 . 2 - 16y 2

98 -16y 2

Rearrange the terms

98 -16y ^2

-16y^2 + 98

Common factor

Factor by grouping

49 . 2 -16^2

-2 (8y^2 - 49)

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