Question

how to factorize 6x sq + x - 1 =0

Answer 1

To factorize first multiply 6 × (-1) = -6

Now get two numbers which when multiplied gives -6 and when added gives the middle coefficient i.e. 1

So, the numbers will be -2 , 3

Now in place of middle coefficient substitute these two value like, 6x^2 + 3x -2x -1 = 0

i.e. 3x ( 2x + 1 ) -1 (2x + 1) = 0

(3x - 1 ) ( 2x+ 1) = 0

x = 1/3 , -1/2.

HOPE THIS HELPS YOU....

Answer 2

Answer:

$(3x - 1)(2x + 1)$

Step-by-step explanation:

$6 {x}^{2} - x - 1$

Now we do the mid term factorization of -x such that the product is -6x² and sum is -x.

Clearly the numbers are 3x and -2x.

Then,

$6 {x}^{2} + 3x - 2x - 1$

$3x(2x + 1) - 1(2x + 1)$

$(3x - 1)(2x + 1)$

Thus we have factorized the given equation.

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