Question

how to factorize : 8xcube + 1 + 12xsq. + 6x
​

Answer 1

Answer:

8x³+12x²+6x

2x(4x²+6x+3)

Answer 2

$\huge☠\star\mathfrak\red{Answer!!☠}$

8x

3

−16x−85=0

⇒8x

3

−16x−125+40=0

⇒(8x

3

−125)−(16x−40)=0

⇒[(2x)

3

−5

3

]−8[2x−5]=0

⇒(2x−5)(4x

2

+25+10x)−8(2x−5)=0

⇒(2x−5){4x

2

+10x+25−8}=0

⇒(2x−5){4x

2

+10x+17}=0

⇒(2x−5)(4x

2

+10x+17)=0