How to factorize
》( b-c)^3 + ( c-d )^3 + ( d-b )^3
shadowsabers03:
Seems that you're a big fan and an addictive player of Shadow Fight 2.
Not that big , actually I didn't have any good picture to put as the profile picture
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This question is based on formula
Solution :- (b - c) ³ + (c - d) ³+ (d - b) ³
= 3(b - c) (c - d) (d - b) AnsWEr
Solution :- (b - c) ³ + (c - d) ³+ (d - b) ³
= 3(b - c) (c - d) (d - b) AnsWEr
I hope i could get some more steps or explanation
This is based on formula (a³+b³+c³= 3abc)
Thanks a lot Leamington
I have not seen a formula like that
At least not in my text book
Are you pulling my leg?
If you don't see in your book then it's your fault
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(b-c)^3+(c-d)^3+(d-b)
=b^3-c^3-3bc(b-c)+c^3-d^3-3cd(c-d)+d^3-b^3-3db(d-b)
(by identity (a-b)^3=a^3-b^3-3ab(a-b))
= -3bc(c-b)-3cd(c-d)-3db(d-b)
(By process of elimination)
There is no such identity like [a^3+b^3+c^3=3abc]
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