Question

How to factorize by splitting the middle term - 6x 2 -3-7x

Answer 1

6x²-3-7x = 0
6x²-7x-3 = 0
6x²-9x+2x-3 = 0
3x(2x-3)+1(2x-3)
(3x+1)(2x-3)
x = -1/3 and x = 3/2

Answer 2

Answer:

The factors of the given expression $6x^2-3-7x$ are $x= \frac {(-1)}{3}$ and $x = \frac{3}{2}$  

To find:

The factors of the given expression $6x^2-3-7x$

Solution:

Here we are finding the factors of the given expression by splitting up the middle terms.

Given that

$6x^2-3-7x\\\\6x^2-3-7x=0\\\\6x^2-7x-3=0$

$\begin{array} { c } { 6 \mathrm { x } ^ { 2 } - 9 \mathrm { x } + 2 \mathrm { x } - 3 = 0 } \\\\ { 3 \mathrm { x } ( 2 \mathrm { x } - 3 ) + 1 ( 2 \mathrm { x } - 3 ) = 0 } \\ \\{ ( 3 \mathrm { x } + 1 ) ( 2 \mathrm { x } - 3 ) = 0 } \\\\ { 3 x + 1 = 0 } \\\\ { x = - \frac { 1 } { 3 } } \\\\ 2x-3=0\\\\ { x = \frac { 3 } { 2 } } \end{array}$

$\mathrm { x } = \frac { - 1 } { 3 } \text { and } \mathrm { x } = \frac { 3 } { 2 }$

The factors of the given expression $6x^2-3-7x$ are $x= \frac {(-1)}{3}$ and $x = \frac{3}{2}$