Question

how to factorize k²‐k+1‐k ??​

Answer 1

k²-k+1-k

=k²-2k+1

=(k)²-2(k)(1)+(1)²

=(k-1)²

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Answer 2

Answer:

k²-2k+1 /using identity =

(k)² +2(k)(1)+(1)² /a² +b²+2ab

[k+1]² /(a+b)²