Question

How to factorize x -8xy3 on the basis of  (x3 - y3)

Answer 1

HEY!!
x – 8xy3
= x (1 – 8y3)
= x [(1)3 – (2y)3]
= x (1 – 2y) [(1)2 + 1 × (2y) + (2y)2] [ a3 – b3 = (a – b) (a2 + ab + b2)]
= x (1 – 2y) (1 + 2y + 4y2)
Thus, x – 8xy3 can be factorized as x (1 – 2y) (1 + 2y + 4y2).

Answer 2

hey dear.. here is ur answer
we can use the formula of (x^3-y^3)
(x-y) (x^2+xy+y^2)
Now,
x(1-8y^3)
x[1^3-(2y)^3]
x[(1-2y) (1^2+1.2y+2y^2)]
x[(1-2y) (1+2y+4y^2)]