how to factorize:x12 +1
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Answered by
1
x¹² + 1
= (x⁴)³ + 1³
= (x⁴ + 1){(x⁴)² - x⁴ + 1 }
= (x⁴ + 1)(x^8 - x⁴ + 1)
hence, (x⁴ + 1) and (x^8 -x⁴ + 1) are the factors x¹² + 1
= (x⁴)³ + 1³
= (x⁴ + 1){(x⁴)² - x⁴ + 1 }
= (x⁴ + 1)(x^8 - x⁴ + 1)
hence, (x⁴ + 1) and (x^8 -x⁴ + 1) are the factors x¹² + 1
Answered by
0
x^12+1
=I can be factorise by using formula a^3+b^3=(a+b)(a^2-ab+b^2)
=(x^4+1)(x^8-x^4+1)
hope its help you
=I can be factorise by using formula a^3+b^3=(a+b)(a^2-ab+b^2)
=(x^4+1)(x^8-x^4+1)
hope its help you
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