How to find 3 numbers whose product and sum are equal?
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1+2+3=1×2×3
6=6
let 1,2 and 3 be x,y and z.
x+y+z=xyz.
But all of these should be consecutive(natural) numbers.
6=6
let 1,2 and 3 be x,y and z.
x+y+z=xyz.
But all of these should be consecutive(natural) numbers.
Answered by
0
1 2 and 3 are these number
1+2+3=(1) (2)(3)
x+y+z=xyz
1+2+3=(1) (2)(3)
x+y+z=xyz
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