how to find 50th derivative of a function ?
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Take the derivative a few times and look for a pattern.
For example, we can find the derivative of f(x) = e^(3x) this way:
f(x) = e^(3x)
f ' (x) = 3e^(3x)
f '' (x) = 9e^(3x)
f ''' (x) = 27e^(3x)
f^(4) (x) = 81e^(3x)
It looks like the pattern is that, each time we take the derivative, we multiply the function we had before by 3.
Multiplying f(x) by 3 fifty times gives (3^50)e^(3x).
So the 50th derivative of e^(3x) is (3^50)e^(3x).
For example, we can find the derivative of f(x) = e^(3x) this way:
f(x) = e^(3x)
f ' (x) = 3e^(3x)
f '' (x) = 9e^(3x)
f ''' (x) = 27e^(3x)
f^(4) (x) = 81e^(3x)
It looks like the pattern is that, each time we take the derivative, we multiply the function we had before by 3.
Multiplying f(x) by 3 fifty times gives (3^50)e^(3x).
So the 50th derivative of e^(3x) is (3^50)e^(3x).
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we find the 1st derivative , then the second derivative, and so on...
We could find a pattern of the n th derivative.
f(x) = a x^n a and n are constants.
if n < 50, f ⁵° = 0
if n = 50 , f ⁵° = 50! * a
if n > 50, f ⁵° = n (n-1)..(n-49) a x^(n-50)
=========================
f(x) = a Sin bx
f ' = a b cos bx
f '' = - a b² Sin bx = - b² f
f ³ = - a b³ Cos bx = - b² f '
f ⁴ = a b⁴ Sin bx = - b² f '' = b⁴ f
f ⁵ = a b⁵ Cos bx = - b² f ³ =
f ⁶ = - a b⁶ Sin bx = - b² f ⁴ = - b⁶ f
f ⁷ = - a b⁷ Cos bx = - b² f ⁵
f ⁸ = a b⁸ Sin bx = b⁸ f
so f ⁴⁸ = b⁴⁸ f
f ⁴⁹ = b⁴⁹ a Cos bx
f ⁵° = - b⁵° a Sin bx = - b⁵° f
==========================
f(x) = Log ax
f ' = a x⁻¹ f '' = - a x⁻² f ³ = 2 a x⁻³ f ⁴ = - 3! x⁻⁴
so f ⁵° = - 49! x⁻⁵°
We could find a pattern of the n th derivative.
f(x) = a x^n a and n are constants.
if n < 50, f ⁵° = 0
if n = 50 , f ⁵° = 50! * a
if n > 50, f ⁵° = n (n-1)..(n-49) a x^(n-50)
=========================
f(x) = a Sin bx
f ' = a b cos bx
f '' = - a b² Sin bx = - b² f
f ³ = - a b³ Cos bx = - b² f '
f ⁴ = a b⁴ Sin bx = - b² f '' = b⁴ f
f ⁵ = a b⁵ Cos bx = - b² f ³ =
f ⁶ = - a b⁶ Sin bx = - b² f ⁴ = - b⁶ f
f ⁷ = - a b⁷ Cos bx = - b² f ⁵
f ⁸ = a b⁸ Sin bx = b⁸ f
so f ⁴⁸ = b⁴⁸ f
f ⁴⁹ = b⁴⁹ a Cos bx
f ⁵° = - b⁵° a Sin bx = - b⁵° f
==========================
f(x) = Log ax
f ' = a x⁻¹ f '' = - a x⁻² f ³ = 2 a x⁻³ f ⁴ = - 3! x⁻⁴
so f ⁵° = - 49! x⁻⁵°
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