how to find a log value plz answer fast
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You must first learn the fundamental principles of logarithmic rules
Log(mn) = log m + log in
Log(m/n)= log m- log m
Log(10^n) = n
Log(m^n) = n log m
By byhearting the below values and above formulas you can do some thing really great .
Split the number into diffrent combinations.
log 2 = 0.301
log 3 = 0.477
log 5 = 0.699
log 7 = 0.845
For example if you are asked to find
log(24)
We can split 24 as 2*2*2*3
Log(2³*3)
= log(2³)+log(3)
= 3 log 2 + log3
= 3(.301)+(.477)
=.903+.477
=1.380
In this way you can perform things easily.
Log(mn) = log m + log in
Log(m/n)= log m- log m
Log(10^n) = n
Log(m^n) = n log m
By byhearting the below values and above formulas you can do some thing really great .
Split the number into diffrent combinations.
log 2 = 0.301
log 3 = 0.477
log 5 = 0.699
log 7 = 0.845
For example if you are asked to find
log(24)
We can split 24 as 2*2*2*3
Log(2³*3)
= log(2³)+log(3)
= 3 log 2 + log3
= 3(.301)+(.477)
=.903+.477
=1.380
In this way you can perform things easily.
shubhangi5062:
okay
but now also I didn't got how to find the log value
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delhi
okay
what u do
which grade
only katta mean
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