How to find a Pythagorean Triplet with the formula 2m, (m²-1), (m²+1)?
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it is easy m is the main no
2m is the smallest no
m^2-1 is the middle no and m^2+1is the largest no
so if 12 is the smallest no then
2m =12
m=12/2
m=6
the middle no = m^2-1
=12^2-1=144-1=143
and largest no = m^2+1
=12^2+1=144+1=145
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